1. x² + 7x + 12 = 0 tolong siapa saja yg bisa jawab
[tex]x {}^{2} + 7x + 12 = 0[/tex]
[tex]x {}^{2} + 4x + 3x + 12 = 0[/tex]
[tex]x \times (x + 4) + 3(x + 4) = 0[/tex]
[tex](x + 4) \times (x + 3) = 0[/tex]
[tex]x + 4 = 0[/tex]
[tex]x + 3 = 0[/tex]
[tex]x = - 4[/tex]
[tex]x = - 3[/tex]
[tex]x1 = - 4[/tex]
[tex]x2 = - 3[/tex]
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